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____ [38]
2 years ago
15

The answer bNamamakakKkKkkKk

Mathematics
1 answer:
skad [1K]2 years ago
4 0
That is really easy how don't you know
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Cos x = 15÷17
because cos is adjacent side over hypotenuse.
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A rectangular prism has volume 12x3 − 11x2 − 5x. Which expressions can represent the dimensions of the prism?
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The expressions that can represent the dimensions of the prim is (x), (3x+1) and (4x-1).
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A camera has a list price of $579.99 before tax. If the sales tax rate is 7.25%, find the total cost of the camera with sales ta
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Step-by-step explanation:

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2 years ago
Evaluate the expression 3x^2+4x^3 when x=4.
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Step-by-step explanation:

304

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2 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
3 years ago
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