The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
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Answer:
Step-by-step explanation:
1/2 (6x-10) - x
Opening bracket
= 6x/2 - 10/2 - x
= 3x - 5 - x
= 2x - 5
Sorry i’m not positive on how to solve the other ones and i don’t want to teach you wrong but here is the answer to number 3 i hope it helps.
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First, convert
to an improper fraction. Use this rule:
=
/ Your problem should look like:
×
Second, simplify 4 × 6 to 24. / Your problem should look like:
×
Third, simplify 24 + 1 to 25. / Your problem should look like:
×
Fourth, apply this rule:
×
=
/ Your problem should look like:
Fifth, simplify 3 × 25 to 75. / Your problem should look like:
Sixth, simplify 5 × 6 to 30. / Your problem should look like:
Seventh, simplify. / Your problem should look like:
Eighth, convert to mixed fraction. / Your problem should look like:
Answer:
