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____ [38]
3 years ago
15

The answer bNamamakakKkKkkKk

Mathematics
1 answer:
skad [1K]3 years ago
4 0
That is really easy how don't you know
You might be interested in
Find the fifth term in the arithmetic sequence that begins at 1.5 and has a common difference of 6.6.
astraxan [27]
I think it's 34.5 (I need more letters so I'm typing this)
4 0
3 years ago
What is the common ratio between successive terms in the sequence? 2, -4, 8, -16, ​
Marianna [84]

Answer:

the answer is f(x) = n*(-2)

ratio is the wrong word to use, it is for contolled variation in probability. a sequence is controlled by what is known as a function - f(x) is the symbol for a function

Step-by-step explanation:

the following number of the previous one in the sequence is derived by the function f(x)=n*(-2)

2 x -2 = -4 (positive x negative = negative)

-4 × -2 = 8 (negative x negative = positive)

8 x -2 = -16 (positive x negative = negative)

so in the sequence, the trend of -,+ double will go on

7 0
3 years ago
Can someone help me with this and show their work and how they found the answer?
Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

4 0
3 years ago
Which of the following expressions is equal to 5 to the 6th power divided by 5 to the 5th power
Jobisdone [24]
Asey

remember
\frac{x^m}{x^n}=x^{m-n}
so

\frac{5^6}{5^5}=5^{6-5}=5^1=5

8 0
3 years ago
Read 2 more answers
Two consecutive positive numbers are such that the sum of their squares is 113. find the two numbers
Naya [18.7K]

Answer: 7 and 8

<u>Step-by-step explanation:</u>

Let x represent the first number, then x + 1 is the other number.

(x)² + (x + 1)² = 113

x²  +  x² + 2x + 1 = 113    <em>expanded (x + 1)²</em>

2x² + 2x + 1 = 113          <em>added like terms</em>

2x² + 2x - 112 = 0        <em>subtracted 113 from both sides</em>

x² + x - 56 = 0 <em>           divided both sides by 2</em>

(x + 8) (x - 7) = 0        <em>factored polynomial</em>

x + 8 = 0   x - 7 = 0    <em>applied zero product property</em>

x = -8     x = 7  <em>          solved for x</em>

  ↓

not valid since the restriction is that x > 0 <em>(a positive number)</em>

So, x = 7     and     x + 1 = (7) + 1   = 8

8 0
3 years ago
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