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Annette [7]
3 years ago
11

Gareth has a deck of cards with 12 challenge cards and 8 prize cards. Gareth is going to randomly select a card from the deck 14

8 times, replacing the card and shuffling the deck after each selection. What is the best prediction for the number of times Gareth will select a prize card?
Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

Gareth has a deck of cards with 12 challenge cards and 8 prize cards.

=> The probability he selects a prize card: P = 8/(12 + 8) = 8/20 = 0.4

Gareth is going to randomly select a card from the deck 148 times, replacing the card and shuffling the deck after each selection .

=>The randomness is kept same for all selecting times

Then the best prediction for the number of times Gareth will select a prize card:

=> N = 0.4 x 148 = 59.2 = 59 times

Hope this helps!

:)

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Suppose you had d dollars in your bank account. You spent $12 but have at least $51 left. How much money did you have initially?
PtichkaEL [24]

For this case we must raise an inequality.

We have "d" dollars initially and they are spent 12. Then:

d-12

At least 51 dollars remain, then, the sign of inequality is greater or equal in favor of the expressiond-12, that is:

d-12\geq 51

Resolving:

d\geq 51 + 12\\d\geq 63

There are at least 63 dollars left in the account.

Answer:

d-12\geq 51\\d\geq 63

8 0
3 years ago
A bicycle tire has a radius of 11 inches. To the nearest inch, how far does the tire travel when it makes 7 revolutions?
jok3333 [9.3K]

Answer:

d = 483.56 inches

Step-by-step explanation:

We have,

Radius of a bicycle tire is 11 inches. It is required to find the distance traveled by the distance covered by the tire when it makes 7 revolutions. One revolution means the circumference of circle. So,

C=2\pi r\\\\C=2\times 3.14\times 11\\\\C=69.08\ \text{inches}

In 7 revolution, it will cover a distance of 7C i.e.

C=69.08\times 7\\\\C=483.56\ \text{inches}

So, the tire will cover a distance of 483.56 inches in 7 revolutions

8 0
3 years ago
If you want to convert yards to feet what operation would you use
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3 years ago
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How would you write the expression the product 18 and a number b?
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Subtraction: 18 - b
Addition: 18 + b
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6 0
3 years ago
Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

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                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
4 years ago
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