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Rus_ich [418]
2 years ago
10

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Find the gradient of the linear relation
Mathematics
2 answers:
vladimir1956 [14]2 years ago
8 0
  • 3y-5x=10

Isolate y

  • 3y=5x+10
  • y=5/3x+10/3

Compare to slope intercept form y=mx+b

Slope=m=5/3

kompoz [17]2 years ago
7 0

Answer:

\dfrac{5}{3}

Step-by-step explanation:

To find the gradient (slope) of the given <u>linear relation</u>, use <u>arithmetic operations</u> to isolate y:

Given relation:

3y-5x=10

Add 5x to both sides:

\implies 3y-5x+5x=10+5x

\implies 3y=5x+10

Divide both sides by 3:

\implies \dfrac{3y}{3}=\dfrac{5}{3}x+\dfrac{10}{3}

\implies y=\dfrac{5}{3}x+\dfrac{10}{3}

<u>Slope-intercept form of a linear equation</u>

y = mx+b

where:

  • m is the slope (gradient)
  • b is the y-intercept

Comparing the rewritten equation with the slope-intercept formula, the gradient (slope) of the given linear relation is ⁵/₃.

Learn more about linear equations here:

brainly.com/question/27317293

brainly.com/question/27781455

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Write an equation of the line that is perpendicular to -x+y=15 and passes through the point (2,-5)
hichkok12 [17]
2-5=15 

2+5=15

i think . sorry if its wrong
3 0
3 years ago
What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0?
Dmitry_Shevchenko [17]

Step-by-step explanation:

since the coefficient is the same for the fist three they have the same equation.

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7 0
2 years ago
Solve x2 + 6x = 7 by completing the square. Which is the solution set of the equation?
Pavel [41]
X^2 + 6x = 7
Divide 6 by 2 and square the result and add to both sides of the equation.
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3 0
3 years ago
Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation
mash [69]

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

5 0
3 years ago
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melomori [17]

Answer:

7 = 0(-2) + b

Step-by-step explanation:

4 0
4 years ago
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