2-5=15
2+5=15
i think . sorry if its wrong
Step-by-step explanation:
since the coefficient is the same for the fist three they have the same equation.
the reason: there can only be one line that goes through one point with a specific coefficient.
X^2 + 6x = 7
Divide 6 by 2 and square the result and add to both sides of the equation.
6/2 = 3 3^2 = 9 x^2 + 6x + 9 = 7 + 9
x^2 + 6x + 9 = 16
(x+3)^2 = 16
x+3 = +- Sqrt 16) = +-4
x = -3+4 = 1
x = -3-4 = -7
Answer:
D
Step-by-step explanation:
Lets go case by case.
Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.
Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!
Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!
(x-4)=0 only for x=4, and as 4 is not a root, C NO!
The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!
D is the only correct option!
Answer:
7 = 0(-2) + b
Step-by-step explanation: