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Tpy6a [65]
3 years ago
6

Find the equation of the parabola with vertex (1,3) and focus (1/2,3).

Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

A (y-3)^2 = -2(x-1) is the correct choice :)


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Help me find area and perimeter of this problem
mylen [45]

Answer: 16.28

Step-by-step explanation: You need to find the area of the half circle so 4*3.14 dvided by 2 that is 6.28 then for the tryangle you do base times hight devided by 2 and you get 10 so add then and it should be 16.28

7 0
4 years ago
Select the equation that represents the problem. Let × represent the unknown number.
kondor19780726 [428]

Answer:

the is option d cause big number is divided by small ones.

Step-by-step explanation:

hope it's right

5 0
3 years ago
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6x+12 factorizar mediante a factor comun<br>​
Art [367]
6(x+2)
you just factor 6 from the expression
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6 0
3 years ago
Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti
ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a.3x+3y=8

Differentiate w.r.t x then we get

3+3\frac{dy}{dx}=0

3\frac{dy}{dx}=-3

\frac{dy}[dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

b.3x+3y=8

3y=8-3x

y=\frac{8-3x}{3}

Differentiate w.r.t x then we get

\frac{dy}{dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

8 0
3 years ago
How do you find the x intercepts of 3x^(5/3) - 4x^(7/3)
kaheart [24]
Set the whole expression = to 0 and solve for x.

3x^(5/3) - 4x^(7/3) = 0.  Factor out x^(5/3):     x^(5/3) [3 - 4x^(2/3)] = 0

Then either x^(5/3) = 0, or 3 - 4x^(2/3) = 0.

In the latter case, 4x^(2/3) = 3. 

To solve this:  mult. both sides by x^(-2/3).  Then we have

4x^(2/3)x^(-2/3) = 3x^(-2/3),            or 4 = 3x^(-2/3).  It'd be easier to work with this if we rewrote it as

4           3
---  = --------------------
1            x^(+2/3)

Then 

4
---  = x^(-2/3).  Then, x^(2/3) = (3/4), and x = (3/4)^(3/2).  According to my     3                      calculator, that comes out to x = 0.65 (approx.)

Check this result!  subst. 0.65 for x in the given equation.  Is the equation then true?

My method here was a bit roundabout, and longer than it should have been.  Can you think of a more elegant (and shorter) solution?
7 0
3 years ago
Read 2 more answers
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