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3 years ago

Find the value of x to the nearest tenth. tan Xº = 31

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer: the answer is 88.2 and your welcome!!

Step-by-step explanation:

Tan x=31

x= tan^-1 (31)

x=88.2 degrees

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Karina and Perry are cleaning up litter in the park for community service hours. Karina and Perry both claim they have covered t

alexgriva [62]

Answer:

Perry's claim is correct while Karina is incorrect

Step-by-step explanation:

Question is incomplete (See Attachment)

First, we need to determine the area covered by Karina and Perry

For Karina, there are 9 square boxes each of which has an area of 1 unit sq

So:

$Karina = 9 * 1\ unit^2$

$Karina = 9\ unit^2$

For Perry:

There are 18 square boxes, each of which has an area of 1 unit sq.

So:

$Perry = 18 * 1\ unit^2$

$Perry = 18\ unit^2$

Comparing both areas, we can conclude that <em>Perry's claim is correct while Karina is incorrect</em>

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2 years ago

Printer allows for optional settings with a panel of sixon-off switches in a row. how many different settings can she select if

Leokris [45]

There are 2×2×2×2×2×2 = 2⁶ = 64 possible settings.

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Each switch can be in 2 positions, and for each of those, the other switches can have all possible settings. 1 switch has 2 settings. 2 switches will have 2×2 settings. 3 switches will have 2×2×2 settings.

6 0

3 years ago

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

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