Answer:
see below
Step-by-step explanation:
First of all, you want to find the data set the matches the extreme values of 5 and 35. That eliminates the 2nd and 4th choices.
Then you want to find the data set that has a median of 15. The first data set has a middle value (median) of 20, so that choice is eliminated.
The data set of the 3rd choice matches the box plot extremes, median, and quartile values.
Answer: The answer is the first matrix. Image attached.
Step-by-step explanation: Given that Dante is solving the system of equations:

In solving the above system of equations, Dante writes the row echelon form of the matrix. We are to select the correct row echelon of the matrix that he wrote.
We know that a matrix is said to be in row echelon form if the leading entry in each nonzero row is a 1 and each column containing a leading 1 has zeros everywhere else.
In the given options, these conditions are satisfied by the first option only. And also, if we write the solution from this matrix, we will have
r = -1, s = 0 and t = 3.
If we substitute these values in the given system, it will get satisfied.
Thus, the first matrix, attached herewith, is the correct matrix.
Answer:
72 units^2
Step-by-step explanation:
Step-by-step explanation:
Correct option is
Correct option isD
Correct option isDLMN=30
Correct option isDLMN=30 Solve:
Correct option isDLMN=30 Solve: Given,
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)⇒L=log7(