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Sophie [7]
2 years ago
6

Solve each given equation, show your work, and provide a complete sentence. Tell whether is has one solution, an infinite number

of solutions, or no solutions
A: 6r + 7 = 13 + 7r

B: -14 + 6b + 7 - 2b = 1 + 5b

C: 8x + 4(4x + 3) = 4(6x + 4) - 4​
Mathematics
1 answer:
alekssr [168]2 years ago
6 0

Step-by-step explanation:

Correct option is

Correct option isD

Correct option isDLMN=30

Correct option isDLMN=30 Solve: 

Correct option isDLMN=30 Solve:  Given, 

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that 

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)⇒L=log7(

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In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

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