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Sophie [7]
2 years ago
6

Solve each given equation, show your work, and provide a complete sentence. Tell whether is has one solution, an infinite number

of solutions, or no solutions
A: 6r + 7 = 13 + 7r

B: -14 + 6b + 7 - 2b = 1 + 5b

C: 8x + 4(4x + 3) = 4(6x + 4) - 4​
Mathematics
1 answer:
alekssr [168]2 years ago
6 0

Step-by-step explanation:

Correct option is

Correct option isD

Correct option isDLMN=30

Correct option isDLMN=30 Solve: 

Correct option isDLMN=30 Solve:  Given, 

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that 

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)

Correct option isDLMN=30 Solve:  Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)⇒L=log7(

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can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
2 years ago
3/8 rounded to the nearest thousand​
ioda

19/50

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5 0
2 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
3 years ago
Julie knows that the adult population gets, on average, eight hours of sleep each night. A hypothesis test can help her see if c
Mamont248 [21]

Answer:

-3.64

Step-by-step explanation:

6 0
3 years ago
Find the complete factored form of the polynomial <br> 30ab^4-5a^6
anzhelika [568]

Answer:

5a(6b^{4} - a^{5})

Step-by-step explanation:

Given

30ab^{4} - 5a^{6} ← factor out 5a from each term

= 5a(6b^{4} - a^{5} ) ← in factored form

5 0
2 years ago
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