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goldfiish [28.3K]
3 years ago
5

Let u=  (-1,3) and w =(2,4) Find the resulting vector of 2u-4w  in component form..

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0
Very simple. You just use the vectors as normal numbers, and multiply the coordinates with 2 and 4 like this: 

2*u = 2* (2,4) = (4,8)
4*w = 4* (-1,3) = (-4,12)

(4,8) - (-4,12) = (8,-4)

So the vector has the coordinates (8,-4)

hram777 [196]3 years ago
4 0
\bf \begin{cases}
u=  (-1,3)\\
w =(2,4)\\
----------\\
\textit{scalar multiplication}\\
2u\implies 2(-1,3)\implies 2\cdot -1,2\cdot 3\\
\qquad -2,6\\
4w\implies 4(2,4)\implies 4\cdot 2,4\cdot 4\\
\qquad 8,16\\
----------\\
2u-4w\\
(-2,6)-(8,16)\implies (-2-8\ ,\ 6-16)
\end{cases}
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The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir
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\displaystyle\\
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7 0
3 years ago
If Upper A equals StartSet x | x is an even integer EndSet commaA={x | x is an even integer}, Upper B equals StartSet x | x is a
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Answer:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Step-by-step explanation:

A={x | x is an even integer}

B={x | x is an odd integer},

C={2, 3, 4, 5},

D={8, 9, 10, 11}.

A union of two or more sets is the collection of the members of the sets in a set without repeating any element.

Given sets C and D above, the union of the two sets is the set:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Note: The Intersection is the collection of sets that are common to C and D. in this case no element is common, therefore the intersection is a Null Set.

8 0
3 years ago
15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 +5% sales tax what was the t
Artist 52 [7]

Answer:

$478.80

Step-by-step explanation:

We have been given that 15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 plus 5% sales tax.

First of all, we will find cost of each meal with tax as:

\text{Cost of each meal with tax}=\$12+\$12\times \frac{5}{100}

\text{Cost of each meal with tax}=\$12+\$12\times 0.05

\text{Cost of each meal with tax}=\$12+\$0.6

\text{Cost of each meal with tax}=\$12.6

Now, we will find total persons at the sport banquet as:

\text{Total persons at banquet}=15+2+21

\text{Total persons at banquet}=38

To find the total cost of food for the banquet, we will multiply cost of food for each person by 38.

\text{Total cost of food for the banquet}=\$12.6\times 38

\text{Total cost of food for the banquet}=\$478.8

Therefore, the total cost of food for the banquet is $478.80.

5 0
3 years ago
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