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Natali5045456 [20]
3 years ago
10

The highest mountain in the world is Mt. Everest, whose peak is 29,029 feet above sea level. But the tallest mountain is Mauna K

ea. The base of Mauna Kea is 19,669 feet below sea level, and its peak is 33,465 feet above its base. How much higher above sea level is Mt. Everest than Mauna Kea?​
Mathematics
2 answers:
atroni [7]3 years ago
7 0

42825 or 9360

Step-by-step explanation:

monitta3 years ago
4 0

So we know that Mt. Everest has a peak that is 29,029 feet above sea level.

To find how much Mauna Kea is above sea level then we would subtract the feet below sea level (19,669ft) from the overall height of the mountain (33,465ft). Like this:

33,465ft - 19669ft = 13,796 feet

Now that we know both mountains height above sea level, we can answer the question.

We will take Everest's height above sea level and subtract Mauna's height above sea level. Like this:

29,029ft - 13,796ft = 15,233

Therefore, Mt. Everest is 15,233 feet taller above sea level than Mauna Kea.

<em>Hope this helps!</em>

<em>- Kay</em>

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Answer:

2g2 - 9g - 1

Step-by-step explanation:

(2g2 -  9g) -  1

2.1     Factoring  2g2-9g-1

The first term is,  2g2  its coefficient is  2 .

The middle term is,  -9g  its coefficient is  -9 .

The last term, "the constant", is  -1

Step-1 : Multiply the coefficient of the first term by the constant   2 • -1 = -2

Step-2 : Find two factors of  -2  whose sum equals the coefficient of the middle term, which is   -9 .

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How many solutions does these equations have? One, infinite or no solutions?
s2008m [1.1K]

Answer:

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a)  Distributive property of multiplication over addtion:

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b) Subtraction property of equalities:

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