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Taya2010 [7]
3 years ago
7

Which is a correct statement about the description " two less than the quotient of a number cubed and sixteen increased by eight

"?
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
[x^3/(16+8)]-2

It says the quotient, dividing, of 'a number', which means a variable or unknown number, cubed, which means to the 3rd power, and 16 increased by 8 (which is 16+ 8) and at the beginning it says 2 less than which means -2.
Pepsi [2]3 years ago
4 0

Answer:

The answer is value is 10,1-2+8 is  B.2-\frac{n^3}{16} +8

Step-by-step explanation:

It says the quotient, dividing, of 'a number', which means a variable or unknown number, cubed, which means to the 3rd power, and 16 increased by 8 (which is 16+ 8) and at the beginning it says 2 less than which means -2.

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90% confidence interval for the difference between the two population means

( -23.4166 , -6.5834)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given first sample size n₁ = 100

Given mean of the first sample x₁⁻ = 178

Standard deviation of the sample S₁ = 35

Given second sample size n₂= 100

Given mean of the second sample x₂⁻ = 193

Standard deviation of the sample S₂ = 37

<u><em>Step(ii):-</em></u>

Standard error of two population means

        se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{s^{2} _{1} }{n_{1} }+\frac{s^{2} _{2} }{n_{2} }  }

       se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{(35)^{2}  }{100 }+\frac{(37)^{2}  }{100 }  }

        se(x^{-} _{1} -x^{-} _{2} ) =  5.093

Degrees of freedom

ν  = n₁ +n₂ -2 = 100 +100 -2 = 198

t₀.₁₀ = 1.6526

<u><em>Step(iii):-</em></u>

<u><em> 90% confidence interval for the difference between the two population means</em></u>

<u><em></em></u>(x^{-} _{1} - x^{-} _{2} - t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2}) , x^{-} _{1} - x^{-} _{2} + t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2})<u><em></em></u>

(178-193 - 1.6526 (5.093) , 178-193 + 1.6526 (5.093)

(-15-8.4166 , -15 + 8.4166)

( -23.4166 , -6.5834)

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