Answer:
√8 ==> 2 units, 2 units
√7 ==> √5 units, √2 units
√5 ==> 1 unit, 2 units
3 ==> >2 units, √5 units
Step-by-step explanation:
To determine which pair of legs that matches a hypotenuse length to create a right triangle, recall the Pythagorean theorem, which holds that, for a right angle triangle, the square of the hypotenuse (c²) = the sum of the square of each leg length (a² + b²)
Using c² = a² + b², let's find the hypotenuse length for each given pairs of leg.
=>√5 units, √2 units
c² = (√5)² + (√2)²
c² = 5 + 2 = 7
c = √7
The hypothenuse length that matches √5 units, √2 units is √7
=>√3 units, 4 units
c² = (√3)² + (4)²
c² = 3 + 16 = 19
c = √19
This given pair of legs doesn't match any given hypotenuse length
=>2 units, √5 units
c² = (2)² + (√5)²
c² = 4 + 5 = 9
c = √9 = 3
legs 2 units, and √5 units matche hypotenuse length of 3
=>2 units, 2 units
c² = 2² + 2² = 4 + 4
c² = 8
c = √8
Legs 2 units, and 2 units matche hypotenuse length of √8
=> 1 unit, 2 units
c² = 1² + 2² = 1 + 4
c² = 5
c = √5
Leg lengths, 1 unit and 2 units match the hypotenuse length, √5
Answer:
Step-by-step explanation:
we are given a quadratic function
we want to figure out the minimum value of the function
to do so we need to figure out the minimum value of x in the case we can consider the following formula:
the given function is in the standard form i.e
so we acquire:
thus substitute:
simplify multiplication:
simply division:
plug in the value of minimum x to the given function:
simplify square:
simplify multiplication:
simplify:
hence,
the minimum value of the function is -155
Nanometer, micrometer, millimeter, centimeter, decimeter, meter, kilometer
IF EC = 8, than we know for sure that the length of AC would be 2 x 8 = 16
The formula to use in determining Rhombus area is
A = (AC . DB)/2 , so the value x could be found with this equation :
72 = 16 (x-1) / 2
72 = (16x -16) /2
72 = 8x - 8
80 = 8x
x = 10
Total surface area of first box = 2(8 * 6.25) + 2(8 * 10.5) + 2(6.25 * 10.5) = 2(50) + 2(84) + 2(65.625) = 100 + 168 + 131.25 = 399.25 sq. ins
Total surface area of second box = 2(9 * 5.5) + 2(9 * 11.75) + 2(5.5 * 11.75) = 2(49.5) + 2(105.75) + 2(64.625) = 99 + 211.5 + 129.25 = 439.75 sq. ins
Hence, the second box requires more material to make.
