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serious [3.7K]
3 years ago
8

It’s the following expression for the given values of X

Mathematics
1 answer:
Georgia [21]3 years ago
4 0

For the given polynomial x^{3} + 3x^{2}  - 7x + 2,x(-2)=20, x(-1)=11, x(0)=2, x(1)= -1, x(2)=8.

Step-by-step explanation:

Step 1:

We substitute the values of x as -2, -1, 0, 1, and 2 in the given polynomial.

The important thing to remember is a negative number powered to an even number will result in an even number and a negative number powered to an odd number will be negative. i.e -2^{4} = 16, -2^{5} = -32.

Step 2:

When x = -2, x^{3} + 3x^{2}  - 7x + 2 = -2^{3} + 3(-2)^{2}  - 7(-2) + 2 = -8+12+14+2 = 20.

When x = -1, x^{3} + 3x^{2}  - 7x + 2 = -1^{3} + 3(-1)^{2}  - 7(-1) + 2 = -1+3+7+2 = 11.

When x = 0,

x^{3} + 3x^{2}  - 7x + 2 = 0^{3} + 3(0)^{2}  - 7(0) + 2 = 0+0+0+2 =2.

When x = 1,

x^{3} + 3x^{2}  - 7x + 2 = 1^{3} + 3(1)^{2}  - 7(1) + 2 = 1+3-7+2 = -1.

When x = 2,

x^{3} + 3x^{2}  - 7x + 2 = 2^{3} + 3(2)^{2}  - 7(2) + 2 = 8+12-14+2 = 8.

Step 3:

So for the given polynomial

x(-2)=20, x(-1)=11, x(0)=2, x(1)= -1, x(2)=8.

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