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3 years ago

Which line is parallel to the line y=x+7

Mathematics

1 answer:

sattari [20]3 years ago

3 0

Answer:

Any line with the same slope. In this case the slope is 1. For example, y=x+4 is parallel to y=x+7.

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Which is the equation of a line that has a slope of 1 and passes through point (5, 3)? A.y = x – 2

gizmo_the_mogwai [7]

Filling in the given values in point-slope equation
y = m(x -x₁) +y1
you have
y = 1(x -5) +3

This simplifies to ...
A. y = x - 2

5 0

3 years ago

Read 2 more answers

Tiana walks 180 feet per minute. How many feet per second does she walk?

Afina-wow [57]

Answer:

3 feet per second

Step-by-step explanation:

180 divided by 60=3

8 0

3 years ago

Read 2 more answers

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

3 years ago

2 5x2 - 19x + 12<br> Standard form

irina [24]

Answer:

5x 2 19x 4

9 6x 2 19x 2

factor 5x 2 19x 4

4x 2 19x 5 0

factor 6x 2 19x 7

6x 2 19x 36Factor 5x^2-19x+12. For a polynomial of the form , rewrite the middle term as a sum of two terms whose product is and whose sum is . Tap for more steps... Factor out of . Rewrite as plus. Apply the distributive property. Factor out the greatest common factor from each group. Tap for more steps...

Step-by-step explanation:

5 0

3 years ago

(x^2 + x - 17) + (x − 4) divide using polynomial long division

Effectus [21]

Answer: x+5 with a remainder of 3 (can also be said as 3/x-4)

Step-by-step explanation: See attachment

6 0

2 years ago