Question

triangle ABC and triangle BCD have vertices A(-6 -7),B(-6,4),C(2,-7),and D(8,4).what is the area,in square units,of trapezoid ABDC which is formed by the two triangles?

Answer 1

Area = 121u^2 .... area = (Parallel side one + parallel side two)/2 X height

Answer 2

Pls find attached file.

and u just need to find the distance by formula

$\sqrt{(y2-y1)^2+(x2-x1)^2}$

where x1,x2,y1,y2 are the cordinate of ABCD trapeziod