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Brilliant_brown [7]
3 years ago
7

triangle ABC and triangle BCD have vertices A(-6 -7),B(-6,4),C(2,-7),and D(8,4).what is the area,in square units,of trapezoid AB

DC which is formed by the two triangles?

Mathematics
2 answers:
monitta3 years ago
8 0
Area = 121u^2 .... area = (Parallel side one + parallel side two)/2 X height
Inessa05 [86]3 years ago
8 0
Pls find attached file.

and u just need to find the distance by formula

\sqrt{(y2-y1)^2+(x2-x1)^2}

where x1,x2,y1,y2 are the cordinate of ABCD trapeziod

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Answer:

  57.1°

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What is the answer to the question
antoniya [11.8K]
The question does not appear sorry
5 0
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