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4 years ago

Use substitution to solve the system of equations.

Mathematics

1 answer:

TEA [102]4 years ago

7 0

Answer:

(4,-5)

Step-by-step explanation:

You can use substitution to substitute the answer options in for x and y or substitute an equation in to find each variable.

Substitute an equation is the traditional method and will allow you to solve without any answer options.

1. Substitute y=x - 9 into 3x+2y=2.

3x+2(x-9) = 2

3x+2x-18=2

5x-18=2

5x=20

x=4

2. Substitute x=4 into y=x-9.

y = 4-9

y=-5

(4,-5) is the solution.

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3 years ago

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3 years ago

Read 2 more answers

Find (w² + 1)(w³ - w + 1).

Citrus2011 [14]

Answer:

Product is $w^5+w^2-w+1$

Step-by-step explanation:

Given: $(w^2+1)(w^3-w+1)$

Simplify the product of polynomial.

It is product of binomial with trinomial.

$\Rightarrow (w^2+1)(w^3-w+1)$

$\Rightarrow w^2(w^3-w+1)+1(w^3-w+1)$ (Distributive property)

$\Rightarrow w^2\cdot w^3-w^2\cdot w+w^2\cdot 1+w^3-w+1$ (Distributive property)

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Product is $w^5+w^2-w+1$

7 0

4 years ago

What’s the correct answer for this?

harkovskaia [24]

Answer:

(x + 5)² + (y - 7)² = 13

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 5, 7) and r = $\sqrt{13}$ , thus

(x - (- 5))² + (y - 7)² = ( $\sqrt{13}$ )² , that is

(x + 5)² + (y - 7)² = 13 ← equation of circle

4 0

3 years ago

PLEASE HELP ME I ASAP I WILL MARK YOU BRAINLIEST

kramer

<h3>Function 1 : </h3>

Observe the abscicca and ordinates

*Note that:- y-coordinate is ordinate and x-coordinate is abscicca.

The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

*Note that:- The point of the graph where the function meets y-axis is called y-intercept.

The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

$\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}$

Thus, Option C is the correct choice!!~

7 0

3 years ago