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3 years ago

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A baseball catcher is performing a stunt for a television commercial. He will catch a baseball (mass 145 g) dropped from a heigh

t of 60.0 m above his glove. His glove stops the ball in 0.0100 s. What is the force exerted by his glove on the ball?

1 answer:

Elodia [21]3 years ago

6 0

Answer:

174kN

Step-by-step explanation:

F ( force) = mass (m) × acceleration (a)

From equations of motion

h = ut + 1/2at^2

h = 60m, t = 0.01s, u = 0m/s

60 = 1/2×a×0.01^2

a = 60×2/1×10^-4 = 1.2×10^6m/s^2

Mass (m) = 145g = 145/1000 = 0.145kg

F = ma = 0.145×1.2×10^6 = 174000N = 174000/1000 = 174kN

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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

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Answer:

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37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

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3 years ago

What is the circumference of the base

katrin2010 [14]

43.96

Explanation:

C=2pi(r)
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kaheart [24]

Answer:

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Step-by-step explanation:

Given

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Required

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$Volume = Length * Width * Height$

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3 years ago

What is -3-(-3) negative three minus -3

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The answer would be 0

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3 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

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Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

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= 0.001

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$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

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= $\mu = \frac{1}{0.001}$

= 1000

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= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

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b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

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= $ 0.50

Since the answer is negative, we are expected to make a loss.

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