Question

Does the table represent a linear function ??

Answer 1

Answer:

No.

Step-by-step explanation:

The points from the table need to have a constant slope for the function to be linear.

Slope is rise over run.

$m=\frac{y_2-y_1}{x_2-x_1}$

For (1,1) and (2,2):

$m=\frac{2-1}{2-1}=\frac{1}{1}=\boxed{1}$

The slope is 1.

For (3,6) and (4,24):

$m=\frac{24-6}{4-3}=\frac{18}{1}=\boxed{18}$

The slope is 18.

1 ≠ 18

Since the slopes of the points are no consistent, the table represents a nonlinear function.

Therefore,

The table does NOT represent a linear function.

Answer 2

No, because the points on the table need to have a constant slope for the function to be linear.