Using Newton's Second Law: F=m a, calculate the mass

The mean number of hours of part-time work per week for a sample of 526526 college students is 2828. If the margin of error for

sveta [45]

Answer:

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

Step-by-step explanation:

A confidence interval has the following format.

$\mu_{x} \pm M$

In which $\mu_{x}$ is the mean of the sample and M is the margin of error.

In this problem, we have that:

$\mu_{x} = 28, M = 2.2$

$\mu_{x} - M = 28 - 2.2 = 25.8$

$\mu_{x} + M = 28 + 2.2 = 30.2$

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

4 0

3 years ago

The triangle circumscribes the circle. Find the perimeter of the triangle. <br> PLEASE HELP

vazorg [7]

The thing about that problem is that when the circle is inscribed inside that triangle, the side measures created are doubled. By that I mean that the 9 on the top right is also the measure of the top left. Same thing for the 13 and the 16. The lower left unmarked side length is 13, the lower right side length is 16. Now add it all up: 9+9+13+13+16+16

3 0

3 years ago

Read 2 more answers

I need the answers for these pls help

DanielleElmas [232]

Answer:

1)

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

2)

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

The measure of an central angle is equal to the measure of its subtended arc
The measure of a circle is 360°
Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

1)

In circle O

A.

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

B.

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

C.

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

D.

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

2)

1]

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

2]

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

8 0

4 years ago

The graph shown below is a scatter plot:

Verdich [7]

I don’t see a point so how am I supposed to answer

8 0

3 years ago

4. Pandora is gathering flowers to decorate her

Monica [59]

Answer:

148

Step-by-step explanation:

In this problem, Pandora has:

- 2 baskets that can hold 38 roses each

- 3 baskets that can hold 24 roses each

Here we want to calculate the total amount of roses that Pandora must get in order to fill all the baskets.

The first 2 baskets can contain a number of roses equal to:

$n_1 = 2 \cdot 38 = 76$

While the other 3 baskets can contain a number of roses equal to:

$n_2=3\cdot 24 =72$

Therefore, the total number of roses that can be contained in the 5 baskets is:

$n=n_1+n_2=76+72=148$

5 0

3 years ago