Question

Help please...I don't get this (40 points and I'll give brainliest)

Answer 1

A x = 0

using the law of exponents $a^{0}$ = 1

for (6² )^ x = 1 then x = 0

B note that $6^{0}$ = 1 ⇒ x = 1

2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)

= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)

= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)