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3 years ago

W=1000M-200 rearrange your make M the subject

Mathematics

1 answer:

Anton [14]3 years ago

7 0

Answer:

M = $\frac{w+200}{1000}$

Step-by-step explanation:

Given

w = 1000M - 200 ( isolate 1000M by adding 200 to both sides )

w + 200 = 1000M ( divide both sides by 1000 )

$\frac{w+200}{1000}$ = M

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Radical form of f(x)=3+2 in X

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A where and a cylinder have the same radius and height . The volume of the cylinder is 48 cm 3. What is the volume of the sphere

SOVA2 [1]

Given:

Sphere and cylinder have same radius and height.

Volume of the cylinder = 48 cm³

To find:

The volume of the sphere.

Solution:

Radius and height of cylinder are equal.

⇒ r = h

Volume of cylinder:

$V=\pi r^2h$

Substitute the given values.

$48=\pi r^2r$ (since r = h)

$48=\pi r^3$

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Divide by 3.14 on both sides.

$$\frac{48}{3.14} =\frac{3.14\times r^3}{3.14}$

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Taking cube root on both sides, we get

2.48 = r

The radius of the cylinder is 2.48 cm.

Sphere and cylinder have same radius and height.

Volume of sphere:

$$V=\frac{4}{3} \pi r^3$

$$V=\frac{4}{3} \times 3.14 \times (2.48)^3$

$V=63.85$

The volume of the sphere is 63.85 cm³.

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3 years ago

A-(buc)=(A-b)u(A-c)

kupik [55]

Step-by-step explanation:

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3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

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3 years ago