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anastassius [24]
3 years ago
11

Steven runs a pizza sho. Since he added breakfast pizza to the menu 54 out of 78customers have ordered the new pizza. If Steven

has 52 customers in the morning how many are likely to order breakfast pizza?
Mathematics
1 answer:
Wittaler [7]3 years ago
5 0
54 * 100 / 78 = 69.23% of costumers order the new pizza.
52 costumers * 69.23% = 35.9996 costumers.

Now just round up and about 36 costumers will order breakfast pizza.

Hope this helps :)
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tatiyna
The answer is 194.59

(72 x 100) / 37 = 194.59
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2 years ago
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The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
2(n+5)=-2 step by step plz
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Answer:

n=-6

Step-by-step explanation:

2(n+5)=-2

distribute

2(n+5)

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2n+10

2n+10=-2

subtract 10 from both sides

10-10=0

-2-10=-12

2n=-12

divide each side by 2

2n/2=n

-12/2=-6

n=-6

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3 years ago
ωнι¢н σƒ тнє ƒσℓℓσωιηg ιѕ тнє ρσѕιтιση ѕ(10) σƒ тнє мσνιηg вσ∂у αт тιмє т=10ѕ, gινєη тнαт ιтѕ α¢¢єℓєяαтιση, α(т)=9.8 м/ѕ^2 , ιηι
jek_recluse [69]
I am eng k ...................
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13. * 7 points 13 A ladder is 50 feet and cast a 25 foot shadow. Mark is 6 feet how long would his shadow be? A 25 feet B 32 fee
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Answer:

3

Step-by-step explanation:

Hope this helps :)

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