Answer:
v= 80, t=100
Step-by-step explanation:
yea
Answer:
obtuse
Step-by-step explanation:
it's obvious if it was acute it would be tiny
The situation will be represented by linear equation, this is given by:
y=ax+b
where:
a=slope=rate
b=y-intercept
from our situation:
a=-1/20
b=5 ft
thus the equation modeling the situation will be:
y=-1/20x+5
Answer: y=-1/20x+5
Answer:
need points
Step-by-step explanation:
is this a question
The reflection line is located at y = -x
For point J, x is -2, so y = -(-2), which equals 2.
When it is a reflection across Y, the X values remain the same.
Find the distance of the Y point to the reflection line,
The distance from -1 to 2 is 3 units.
The new point needs to be the same distance from the reflection line.
2 + 3 units = 5.
Point J' would be (-2,5)