Answer:
x^4 + 2x^3 + 3x^2 + 2x + 2 = 0
Step-by-step explanation:
The computation of the polynomial equation of the lowest degree is shown below
As we know that the complex roots would always arise in the conjucate pairs
As -i is a root, i is also a root
As -1 + i is a root
And, -1 is also a root
Now the polynomial equation would be
(x + i)(x - i)(x + 1 - i)(x + 1 - i) = 0
(x^2 - i^2)[(x + 1)^2 - i^2] = 0
(x^2 + 1)[(x + 1)^2 + 1] = 0
(x^2 + 1)(x^2 + 2x + 2) = 0
x^4 + 2x^3 + 3x^2 + 2x + 2 = 0
Pretty sure you just subtract,
-26,000
And -9,500
And the answer is; 35,500
Answer:
-√(1 - 2x) + C
Step-by-step explanation:
1/√(1-2x)
We want to integrate it. Thus;
∫1/√(1 - 2x) dx
Let u = 1 - 2x
Thus;
du/dx = -2
Thus, dx = -½du
Thus,we now have;
-½∫1/√(u) du
By application of power rule, we will now have;
-½∫1/√(u) du = -√(u) + C
Plugging in the value of u, we will have;
-√(1 - 2x) + C
Answer:
Step-by-step explanation:
The given logarithmic expression is
Recall and use the product property of logarithm: 
;
This implies that;
Recall again that; 
;
We apply this property to get;
The qoutient is 8 to your question.
