Answer:
<h2>This equation has no natural roots.</h2>
Step-by-step explanation:

Answer:

Step-by-step explanation:
Given

Required
How it'd be displayed on a calculator
Standard calculators, today are built to always convert huge numbers or extremely small number to scientific notations;
This was done to allow the calculator fit each values on its screen
is such a big number that it'll require the calculator to display it using scientific notations;
So, basically we have to convert
to scientific notaton;
This is achieved by replacing
with 
So,
is equivalent to 
Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
Answer:490pi
Step-by-step explanation:just trust me
Answer:
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
Step-by-step explanation:
g(x) = -3(1/2)^x
Putting values of x
x g(x)
-2 -3(1/2)^-2 = -12
-1 -3(1/2)^-1 = -6
0 -3(1/2)^0 = -3
1 -3(1/2)^1 = -3/2
Now, making the graph we will plot
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
The graph is shown in figure below.