Answer:
8.245*10^6
Step-by-step explanation:
scientific notation is known as c*10^n
c : any number from 1-10
n : the power of base 10
the number in our case between 1 and 10 is 8.245
but then we want to move the decimal 6 spaces to the right, so we multiply that by 10^6
An=-31+(n-1)-11 find the eleventh term
a11 = -31 + (-11) (11-1)
a11 = -31 +-11(10)
a11 =-31 +-110
a11 = -142
The quadratic equation in its generic form is:
ax2 + bx + c
To complete squares we must add the following term:
(b / 2) ^ 2
The equation is:
ax2 + bx + c + (b / 2) ^ 2
We have the following equation:
x ^ 2 - 5x + k = 7
By completing squares we have:
x ^ 2 - 5x + (-5/2) ^ 2 = 7 + (-5/2) ^ 2
Rewriting:
x ^ 2 - 5x + 6.25 = 7 + 6.25
Answer:
A constant term should be used to complete the square is:
6.25
Answer:
end of third year = 1,200*(1.02)^3 = 1,273.45 plus
end of second year = 1,200*(1.02)^2 = 1,248.48 plus
end of first year = 1,200*(1.02) = 1,224.00
Total = 3,745.9
Step-by-step explanation:
Answer:
See photo below
Add arrows to the two ends of the parabola.
Step-by-step explanation:
To sketch this quadratic function, we to connect three dots: the two roots and a vertex.
The given roots are -1 and 1.
Draw <u>two dots at the x-intercepts</u>, which are (-1, 0) and (1, 0).
Vertex dot: V (x, y)
The vertex x-coordinate always in the middle of the two roots. The middle of -1 and 1 is 0. That's the same as the y-axis.
V (0, y)
Since the function increases when x < 0, the parabola will <u>open up</u>.
We read from left to right. The greater numbers are towards the top of the page.
<u>You can put the vertex anywhere on the y-axis that is below the x-axis.</u>
