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professor190 [17]
3 years ago
10

Which of the following statements is true? A. 15-0=0 B. 0÷15=0 C. 15+0=0 D. 15÷0=0​

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer:

B) 0:15=0

Step-by-step explanation:

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What is the resulting equation when the expression for y in the second equation is substituted into the first equation? 3x y = 1
Natali5045456 [20]

After putting the value of y from the second equation to the first equation, the resultant equation is x=5.

GIven:

The equations are:

3x + y = 1\\
y = 6 - 4x

It is required to put the value of y from second equation to the first equation.

<h3>How to solve equations?</h3>

The value of y from the second equation is,

&#10;y = 6 - 4x

Now, put this value of y in the first equation as,

3x + y = 1\\&#10;3x+(6 - 4x)=1\\&#10;3x+6-4x=1\\&#10;-x=-5\\&#10;x=5

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is x=5.

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8 0
1 year ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
What is the answer to 1/9 + 3/5
hjlf
32/45 is the answer I believe
3 0
3 years ago
Read 2 more answers
Geometry!<br> Find the length of the short leg
Mrrafil [7]
90 cm because ................................
3 0
3 years ago
PLEASE HELP! GIVEE ME THE 14 ANSWERS FOR THIS FOR BRAINLIEST
gulaghasi [49]

Answer:

Step-by-step explanation:

oh boy

1) 9 < 16

2) -4 < 5

3) 18 > -19

4) -38 < -16

5) 6 > 4

6) -14 > -25

7) -45 > -55

8) -2 > -10

9) -4, -1, 1, 3, 6

10) -15, -13, -5, 8

11) -9, -6, -5, -1, 0

12) -4, -2, 1, 3

13) -10, -9, 7, 8, 11

14) -33, -25, -14, -4, 7

hope this helps <3

6 0
3 years ago
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