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4 years ago

Identify the slope and y-intercept of each linear function's equation.

Mathematics

1 answer:

Stolb23 [73]4 years ago

5 0

Answer:

- x + 3 = y ....... slope = -1 and y-intercept of 3

x - 3 = y ......... slope = 1 and y-intercept of -3

y = 3 x - 1 ......... slope = 3 and y-intercept of -1

y = 1 - 3 x ....... slope = -3 and y-intercept of 1

Step-by-step explanation:

Just read the slope and y intercept from the equations since they are all given in slope-intercept form:

- x + 3 = y ....... slope = -1 and y-intercept of 3

x - 3 = y ......... slope = 1 and y-intercept of -3

y = 3 x - 1 ......... slope = 3 and y-intercept of -1

y = 1 - 3 x ....... slope = -3 and y-intercept of 1

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I need 18,19,& 20•ignore my writing

Korolek [52]

Answer:

Part 18) Option D 100 square meters

Part 19) Option A 60 cubic meters

Part 19) Option C. 212 cubic centimeters

Step-by-step explanation:

Part 18) Estimate the surface area of the prism

we know that

The surface area of the prism is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

Find the area of the base B

$B=3.5*7=24.5\ m^{2}$

Find the perimeter of the base P

$P=2*(3.5+7)=21\ m$

we have

$H=2.4\ m$

substitute

$SA=2(24.5)+(21)(2.4)=99.4\ m^{2}$ ----> exact value

Estimate the surface area

we have

$L=3.5=4\ m$ ----> round up

$W=7\ m$

$H=2.4=2\ m$ ----> round down

Estimate the area of the base B

$B=4*7=28\ m^{2}$

Estimate the perimeter of the base P

$P=2*(4+7)=22\ m$

substitute in the formula

$SA=2(28)+(22)(2)=56+44=100\ m^{2}$

Part 19) Estimate the volume of the prism

The volume of the prism is equal to

$V=BH$

we have

$B=3.5*7=24.5\ m^{2}$

$H=2.4\ m$

substitute

$V=(24.5)(2.4)=58.8\ m^{3}$ ----> exact value

Estimate the volume

we have

$L=3.5=4\ m$ ----> round up

$W=7\ m$

$H=2.4=2\ m$ ----> round down

Estimate the area of the base B

$B=4*7=28\ m^{2}$

substitute in the formula

$V=(28)(2)=56\ m^{3}$

Part 20) The volume of the prism is equal to

$V=BH$

we have

$B=6*6.8=40.8\ cm^{2}$

$H=5.2\ cm$

substitute

$V=(40.8)(5.2)=212.16\ cm^{3}$ ----> exact value

Estimate the volume

we have

$L=6\ cm$

$W=6.8=7\ cm$ ----> round up

$H=5.2=5\ cm$ ----> round down

Estimate the area of the base B

$B=6*7=42\ cm^{2}$

substitute in the formula

$V=(42)(5)=210\ cm^{3}$

5 0

3 years ago

Rex paid $250 in taxes to the school district that he lives in this year. This year's taxes were a 12% increase from last year.

Verizon [17]

Answer:

$223.21

Step-by-step explanation:

Last year the amount of taxes was x, an unknown amount. That was 100% of last year's tax cost.

This year, taxes went up by 12%, so this year the taxes are 112% of what they were last year. This year the taxes were 112% of x, and they were $250.

112% of x = 250

1.12x = 250

x = 250/1.12

x = 223.21

Answer: $223.21

8 0

3 years ago

The price of a television was reduced from $2000 to $1400. By what

meriva

Answer:

30%

Step-by-step explanation:

2000-----100%

1400------x%

x=(1400×100)÷2000

X=70%

final we go 100%-70%=30%

Television price reduced for 30%

6 0

3 years ago

What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

Xelga [282]

The answer to the question is d

6 0

4 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago