Your answer would be F(0)=f(-1)
(701+y)/(3+1)<200
(701+y)/4<200
701+y<800
y<99
So the most yards they can allow in the next game is 98 yards
Answer:
Hey mate....
Step-by-step explanation:
This is ur answer.....
<h3>
<em>Points L, J, and K are collinear.</em></h3>
Hope it helps you,
mark me as the brainliest....
Follow me!!
98^2 = (100-2)^2
Using (a-b)^2, we have
= (100)^2-2(100)(2)+(2)^2
= 10000-400+4
= 10004-400
= 9604
The answer is 9604.
Please mark me Brainliest
