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3 years ago

I need to know please help?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

8 0

The correct answer is B.

Masteriza [31]3 years ago

4 0

Answer:

Step-by-step explanation:

4 liters= 4000ml

3,250ml=3,250ml

2.5liters=2500ml

A)3,250-2500= 750 more ml of fabric softener than bleach- so a is not correct and c is correct

4 liters- 2.5 liters=1.5 liters- so b is not correct

4000ml-2500ml=1500 ml-- so d is false as well

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A sequence is defined by the recursive formula f(n + 1) = 1.5f(n). Which sequence could be generated using the formula? –12, –18

Softa [21]

Answer:

The sequence -12 , -18 , -27 , ............ is generated using the formula ⇒ 1st sequence

Step-by-step explanation:

The recursive formula of the sequence is f(n + 1) = 1.5 f(n)

That means there is a constant ratio 1.5 between each two consecutive terms

In sequence -12 , -18 , -27 , ............

The first term is -12

The formula is f(n + 1) = 1.5 f(n)

Use the first term where n = 1 to find the 2nd term

∵ f(1) = -12

- Substitute n by 1 in the given formula

∵ f(1 + 1) = 1.5 f(1)

∴ f(2) = 1.5(-12)

∴ f(2) = -18

Use the second term where n = 2 to find the 3rd term

∵ f(2) = -18

- Substitute n by 2 in the given formula

∵ f(2 + 1) = 1.5 f(2)

∴ f(3) = 1.5(-18)

∴ f(3) = -27

∴ The sequence -12 , -18 , -27 , ............ is generated using the formula

8 0

3 years ago

What is the solution to 2x + 8 > 10 ?

denis-greek [22]

<span>2x + 8 > 10
Subtract 8 from both sides
2x>2
Divide 2 on both sides
Final Answer: x>1</span>

5 0

3 years ago

Read 2 more answers

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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3 years ago

wind resistance varies jointly as an objects surface area and velocity. if an object traveling at 55 miles per hour with a surfa

nikdorinn [45]

Answer:

25 miles per hour

Step-by-step explanation:

Given

$W = Wind\ resistance$

$A = Surface\ Area$

$V = Velocity$

The joint variation can be represented as:

$W\ \alpha\ A*V$

Where:

$V = 55; A = 20; W = 220$

Required

Find V, when: $A = 55; W = 275$

We have:

$W\ \alpha\ A*V$

Express as an equation

$W= k *A*V$

Where k is the constant of variation

Make k the subject

$k = \frac{W}{A*V}$

When: $V = 55; A = 20; W = 220$

We have:

$k = \frac{220}{20 *55 }$

$k = \frac{220}{1100}$

$k = 0.2$

When: $A = 55; W = 275$

We have:

$k = \frac{W}{A*V}$

Substitute: $A = 55; W = 275$ and $k = 0.2$

$0.2 = \frac{275}{55 * V}$

Make V the subject

$V= \frac{275}{55 * 0.2}$

$V= \frac{275}{11}$

$V= 25$

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3 years ago

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Mariana [72]

The answer would be 71

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3 years ago