A deck of cards contains 10 black cards and 10 red cards. The first card drawn is not replaced before drawing the second card. W
hat is the probability of selecting a red card followed by a red card? 9 38 5 19 1 4 10 19
2 answers:
Answer:
<u>9/38</u>
Step-by-step explanation:
P (1st card red) :
- No. of red cards / Total deck of cards
- 10 / 10 + 10
- 10/20
- 1/2
P (2nd card red) :
- No. of red cards - 1 / Total deck of cards - 1
- 10 - 1 / 20 - 1
- 9/19
P (both) :
- P (1st card red) x P (2nd card red)
- 1/2 x 9/19
- <u>9/38</u>
<h3>
Answer: 9/38</h3>
Reason:
There are 10 red cards out of 10+10 = 20 total.
10/20 = 1/2 is the probability of selecting a red card.
If the red card is not put back (i.e. "no replacement"), then the chances of getting another red card is (10-1)/(20-1) = 9/19
Multiply the two fractions mentioned to get the final answer.
(1/2)*(9/19) = (1*9)/(2*19) = 9/38
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