Answer: 2nd graph and the point is (6,7)
Step-by-step explanation:
Answer:
0.0369
Step-by-step explanation:
normalcdf (1220,1320,900,200) is 0.0369
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
The area is given by:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
The area of the base is:
Ab = (3/2) * (L ^ 2) * (root (3))
Where,
L: side of the hexagon.
Substituting we have:
Ab = (3/2) * (4 ^ 2) * (root (3))
Ab = (3/2) * (16) * (root (3))
Ab = 24raiz (3)
The lateral area is:
Al = (6) * (1/2) * (b) * (h)
Where,
b: base of the triangle
h: height of the triangle
Substituting we have:
Al = (6) * (1/2) * (4) * (6)
Al = 72
The total area is:
A = 24raiz (3) + 72
Answer:
A = 24raiz (3) + 72