Answer:
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Step-by-step explanation:
ANSWER
The new equation is:
EXPLANATION
The given parabola has equation,
This is the parent function.
When we reflect this parabola in the x-axis and then scaled vertically by a factor of 1/8.
The new equation becomes:
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
The least value is the smallest number in a set. So in this case it would be 3 since the first marker marks 3 on the box plot.
