21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
-45
-26x+30
Step-by-step explanation:
So first you let's divide this equation into three parts.
Part one -9x(5x+4)
- Step one: you have to distribute the -9x to the numbers in the parentheses. That would leave us with a -9x*5x = -45
and -9x*4 = -36x - Step two: Put the answers together. That would leave us with -45
-36x.
Part two 10(x+3)
- Step one: you have to distribute the 10 to the numbers in the parentheses. That would leave us with a 10*x = 10x and 10*3 = 30
- Step two: Put the answers together. That would leave us with 10x+30
Part three solve
- Step one: combine and put together what you have solved for. That would leave us with a -45
-36x+ 10x+30 - Step two: combine like terms. The like terms here are -36x and 10x. When you combine them you would get -26x.
- Step three: Write the equation in standard form. Therefore the answer is -45
-26x+30.
Let me know if anything is confusing!
Answer:
The scale factor is 1/2.
Step-by-step explanation:
Before the scale is put into effect, each coordinate is double of after the scale is put into effect. Its ratio of 2:1, so it'd be 1/2.
If it's most likely A. or B.
Correct me if I'm wrong.
But, I hope this helps!
0=0, all numbers are solutions