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bulgar [2K]
3 years ago
8

!!PLEASE ANSWER ASAP!!

Physics
2 answers:
Kaylis [27]3 years ago
7 0

Its B and C, because they both are doing the same thing just one has more rate of work than the other so yea B and C

inessss [21]3 years ago
5 0

The answer is B. The electric screw driver increased the work. You would rather have an electric one than doing it all by hand. Hope this helps!

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Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation 0.070 g. A vending m
Igoryamba

Answer:

The percentage of legal quarters that will be rejected is 1.954 %.

Explanation:

Here we are required to find

P(X<5.48 or X>5.82)

We have μ = 5.67 and  σ = 0.07 where the range is between 5.48 and 5.82 we each z-score given by

z =\frac{x-\mu}{\sigma}

Therefore for 5.48 we have z_{5.48} = \frac{5.48 -5.67}{0.07} = -2.714

and for 5.82 we have   z_{5.82} = \frac{5.82 -5.67}{0.07} = 2.143

Therefore we have the area of interest on the normal distribution chart given by

P(Z<-2.714) + P(Z >  2.143) =  P(Z<-2.714) + (1 - P(Z <  2.143))

+  0.00336 + 1 - 0.98382 = 0.01954

= 0.01954 × 100 = 1.954 %

Therefore 1.954 percentage of legal quarters will be rejected.

3 0
3 years ago
the velocity of a car changes from 10 m/s east to 30m/s east in 4 seconds. what is the acceleration of the car
Zepler [3.9K]
A=(V-Vo)/t=(30-10)/4=20/4=5m/s^2
8 0
4 years ago
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In a photoelectric effect experiment, electromagnetic radiation containing a finite distribution of wavelengths shines on a meta
Sonja [21]

Answer with Explanation:

a.Intensity of radiation is directly proportional to the frequency of radiation

When the intensity of radiation  increases then the frequency of radiation increases and therefore, the number of photo-electrons emitted by the metal increases.

b.When all  of the wavelength in the radiation are increased by the same amount

We know that  

f=\frac{v}{\lambda}

Frequency is inversely proportional to the wavelength.

Therefore, the frequency decrease .

When the frequency decreases then the number of photo-electrons emitted by the metal decrease.

c.When the work function of the metal is increased  then the gain of kinetic energy decreases .

When energy decreases then the number of photo-electrons emitted by the metal decreases.

3 0
4 years ago
An electric field is given by in units of N/C when is in meters. What is the potential difference from point B at (0,7) m to poi
AlladinOne [14]

Complete Question

An electric field is given by E= (5x, 0, 0) in units of N/C when x is in meters. What is the potential difference VA - VB from point B at (0,7) m to point A at (7,0) m? V

Answer:

V_A-V_B=-122.5V

Explanation:

From the question we are told that:

Position of point B=(0,7) m

Position of point A=(7,0) m

Generally the equation for pd across the points is mathematically given by

 V_A-V_B=-\int_0^7(5x)d

 V_A-V_B=-[\frac{5x^2}{2}]_0^7

 V_A-V_B=-[\frac{5(7)^2}{2}]

 V_A-V_B=-122.5V

8 0
3 years ago
Between the ball and the player’s head, there are forces. Which of Newton’s laws does this represent? Support your choice.
Nana76 [90]

Answer:according  to newtons third law for every action force there is an equal in size and opposite in direction reaction force forces always comes in pairs

Explanation:

8 0
2 years ago
Read 2 more answers
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