Answer:
13.524 N
Explanation:
Volume and densities are given as:
ρ1 = 2.6 g/cm³ => 2600 kg/m³ ; V1 = 0.50 L => 0.5 x 10^-3 m³
ρ2 = 1.0 g/cm³ => 1000 kg/m³ ; V2= 0.25 L => 0.25 x 10^-3 m³
ρ3 = 0.7 g/cm³ => 700 kg/m³ ; V3 = 0.4 L => 0.4 x 10^-3 m³
Next is to calculate force exerted on the bottom of the container due to these liquids:
F= ρ1V1g + ρ2 V2 g+ ρ 3 V3g
where ,
ρ= density
V= volume
g= 9.8m/s²
F= g( 2600 x 0.5 x 10^-3 + 1000 x 0.25 x 10^-3 + 700 x 0.4 x 10^-3)
F= 9.8 (1.38)
F= 13.524 N
Therefore, the force on the bottom of the container due to these liquids is 13.524 N
Answer:
Please find the answer in the explanation
Explanation:
Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic field at locations other than the central axis.
What happens as you move away from the center axis toward the coil? The direction of the magnetic compass needle will move in an opposite direction since the direction of the induced voltage is reversed.
What happens above the coil?
the needle on the magnetic compass will be deflected. Since compasses work by pointing along magnetic field lines
Outside the coil? The magnetic compass needle will experience no deflection. Since there is no induced voltage or current.
Below the coil?
The needle will move in an opposite direction.
Answer:
The the average magnitude of the force exerted on the ball by the floor 
N
Explanation:
Given:
Mass of ball 
kg
Initial speed 
Rebound speed 
Contact time interval 
sec
For finding the average magnitude of the force on the ball by the floor is given by,
Here 
N
Therefore, the the average magnitude of the force exerted on the ball by the floor N
Answer:
a) Maximum height reached above ground = 2.8 m
b) When he reaches maximum height he is 2 m far from end of the ramp.
Explanation:
a) We have equation of motion v²=u²+2as
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0²=5.6² + 2 x -9.81 x s
s = 1.60 m
Height above ground = 1.2 + 1.6 = 2.8 m
b) We have equation of motion v= u+at
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0= 5.6 - 9.81 x t
t = 0.57s
Now considering horizontal motion of skateboarder.
We have equation of motion s =ut + 0.5 at²
u = 6.6cos58 = 3.50 m/s
a = 0 m/s²
t = 0.57
Substituting
s =3.5 x 0.57 + 0.5 x 0 x 0.57²
s = 2 m
When he reaches maximum height he is 2 m far from end of the ramp.
Answer:
1. All electromagnetic waves travelS at 3×10⁸m/s in vacuum
2.They are transverse in nature.
3.they can travel through vacuum.( doesn't require any materials for their transmission.
4.They under go phenomena of diffraction,reflection, refraction, interference and polarization.
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