Answer:
The correct answer is:
15/16
Step-by-step explanation:
In a toss of four fair coin, there are possibility of 16 occurrence because a coin have an head and a tail (2).
In 4 coins, we will have : 2⁴ = 16
Let S be the sample space, then:
S = { HHHH, HHHT, HHTT, HTTT, TTTH, TTHH, TTTH, TTTT, HTHT, THTH, HHTH, HTHH, TTHT,THHT, HTTH, THTT}
Let E₁ be the event that at least one head appears:
n(E₁) = 15
∴ Pr (E₁) = n(E₁)/ n(S)
= 15/16
