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Angelina_Jolie [31]
3 years ago
5

The net change in temperature from Neptune to Mars is

Mathematics
1 answer:
azamat3 years ago
4 0
We know that the average temperature surface in neptune is :  - 210 degree Celsius
Thee average temperature surface in mars is : -85 degree Celsius

The net change would be an increase in 125 degree celsius<span />
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21x + 7y = 14 <br> -7y = 10 - 3x <br> btw its Elimination!
patriot [66]

\displaystyle\\\left \{ {{21x+7y=14} \atop {-7y=10-3x}} \right. \\\left \{ {{21x+7y=14} \atop {3x-7y=10}} \right. \\\\\text{We add 2 equations to remove y}\\21x+3x+7y+(-7y)=14+10\\24x=24=>x=1\\\text{We found x, now we can find y. Let's put x=1 into 1st equation}\\21\times1+7y=14\\7y=-7\\y=-1

6 0
3 years ago
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1/2 (n - 4) - 3 = 3 - (2n + 3). Find the value of n.
NikAS [45]

Answer: I think the answer is n=2

Step-by-step explanation:

5 0
3 years ago
Compute the monthly payments for the add on interest loan. The amount of the loan is $8,276.17. The annual interest rate is 5.7%
podryga [215]

The monthly payments for this add on interest loan are of $164.71.

Given Information and Formula Used

It is given that for an add on interest loan,

Principal Amount, p = $8,276.17

Annual Interest Rate, r = 5.7%

Term of the loan, T = 5.5 years

The formula for simple interest is given as follows,

I = (p)(r)(t)/100 ............... (1)

The formula for total amount of add on interest is given by,

A = p + I ....................... (2)

Computing the Interest

Substitute the given values of p, r, and t in the formula (1) of interest to get,

I = (8276.17)(5.7)(5.5)/100

I = 259457.9295/100

I = $2,594.58

Computing the Monthly Payment for Add-on Interest Loan

Substituting the values of p and I in the formula (2), we obtain the total amount as,

A = $ (8276.17 + 2594.58)

A = $ 10,870.75

Monthly payment for the add on interest loan = A/t(in months)

=  $ (10,870.75/66)

= $164.71

Therefore, monthly payments of $164.71 are to be made for the add on interest loan.

Learn more about interest here:

brainly.com/question/26457073

#SPJ1

7 0
2 years ago
What is the equation of the line that passes through the points (6,8) and (-3,2)
Vikki [24]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (6, 8) and (-3, 2). Substitute:

m=\dfrac{2-8}{-3-6}=\dfrac{-6}{-9}=\dfrac{2}{3}\\\\y-8=\dfrac{2}{3}(x-6)\qquad|\text{use distributive property}\\\\y-8=\dfrac{2}{3}x-4\qquad|+8\\\\y=\dfrac{2}{3}x+4\qquad|-\dfrac{2}{3}x\\\\-\dfrac{2}{3}x+y=4\qquad|\cdot(-3)\\\\2x-3y=-12

Answer:

point-slope form: y-8=\dfrac{2}{3}(x-6)

slope-intercept form: y=\dfrac{2}{3}x+4

standard form: 2x-3y=-12

8 0
3 years ago
What is the Area of 4, and 9
Free_Kalibri [48]
The area of 4 and 9 is 36 because you multiply the width and length
5 0
3 years ago
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