All categories

3 years ago

If you divide or multiply by a negative, you must remember to ________ the inequality sign.

Mathematics

2 answers:

Sholpan [36]3 years ago

7 0

When multiplying or dividing, you must remember to flip the inequality sign

I hoped I helped

X8lue83rryX

QveST [7]3 years ago

3 0

FLIP is correct.

Hope this helps :)

You might be interested in

Find the missing side. Round it to the nearest tenth.

Alenkasestr [34]

Answer:

19.1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Is the following situation proportional? Justify your answer. At an arcade, Aisha pays $2 for each game she plays.

Over [174]

Yes, the situation as described is proportional.

Discussion:

According to the question:

We are required to determine if the situation described in the question is proportional.

Since, Aisha pays $2 for each game she plays at the arcade.

In essence, the total amount of money paid by Aisha will depend on the number of games she plays. On this note, the situation is proportional.

Read more on proportional:

brainly.com/question/3202565

7 0

2 years ago

#2 pls I’ll give braniest to whoever replies first, I’m not sure about number 2 pls help.

Oduvanchick [21]

Answer:

D) 525

Step-by-step explanation:

hope this helped!!

4 0

3 years ago

Read 2 more answers

Use the table to write a linear function that relates y to x

Helen [10]

Answer:

y = 2,-6

Step-by-step explanation:

Linear functions are of the form y = mx + b.

each time the number changes in the x, the y increases by 2

7 0

3 years ago

Read 2 more answers

Solve for the sqrt(x-2)+8=x

kirza4 [7]

<h3>Answer: x = 11</h3>

==============================================

Work Shown:

$\sqrt{x-2}+8=x\\\sqrt{x-2}=x-8\\\left(\sqrt{x-2}\right)^2=(x-8)^2 \text{ square both sides}\\x-2=x^2-16x+64\\0=x^2-16x+64-x+2\\0=x^2-17x+66\\x^2-17x+66 = 0\\(x-11)(x-6) = 0\\x-11 = 0 \text{ or } x-6 = 0\\x = 11 \text{ or } x = 6\\$

Those are the two possible solutions . We need to check each possible solution.

Plug in x = 11 then simplify. If we get the same number on both sides, then x = 11 is confirmed.

$\sqrt{x-2}+8=x\\\sqrt{11-2}+8=11\\\sqrt{9}+8=11\\3+8=11\\11=11\\$

We get 11 on both sides, so the solution x = 11 is confirmed.

Repeat for x = 6 as well

$\sqrt{x-2}+8=x\\\sqrt{6-2}+8=6\\\sqrt{4}+8=6\\2+8=6\\10=6\\$

We do not get the same thing on both sides, so x = 6 is not a solution. We consider this extraneous.

4 0

3 years ago