Answer:
y=5x-12
Step-by-step explanation:
find the slope first which is (8-3)/(4-3)=5
Then that’s your slope.
after that plug the x into the equation I wrote so that means y=5(3)-12 and you should get the y value which is simple enough if you know how to do it.
Answer:
1/7
Step-by-step explanation:
We can use the slope formula(k=y₁-y₂/x₁-x₂) to solve this problem
k = 2-1/3-(-4) = 1/7
Step-by-step explanation:
Initially, let the side of the cubical box is 
inches,
So, the volume of the box, 
.
Given that ![g(x)=\sqrt[3]{x} =\sqrt[3]{a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%3D%5Csqrt%5B3%5D%7Ba%5E3%7D)
On doubling the volume of the box, the new volume is 
.
So, ![g(x)=\sqrt[3]{2x} =\sqrt[3]{2a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B2x%7D%20%3D%5Csqrt%5B3%5D%7B2a%5E3%7D)
![\Rightarrow g(x)=\sqrt[3]{2} a \; \cdots (i)](https://tex.z-dn.net/?f=%5CRightarrow%20g%28x%29%3D%5Csqrt%5B3%5D%7B2%7D%20a%20%5C%3B%20%5Ccdots%20%28i%29)
As ![\sqrt[3]{2} >1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%3E1)
, so the graph of ![g(x)=\sqrt[3]{2} a](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B2%7D%20a)
will be above of the 
as shown in the graph.
Answer: 80, 1/12, 5/6
Step-by-step explanation:
Sorry but, there’s nothing attached so I can not help you.
