Answer:
no solution
Step-by-step explanation:
Divide by 4:
3d -1 = 3d
Subtract 3d:
-1 = 0 . . . . . . FALSE
There is no value of d that will make this be true. The equation has NO SOLUTION.
THe given equation is
![y=(1+4x)^{12}](https://tex.z-dn.net/?f=%20y%3D%281%2B4x%29%5E%7B12%7D%20)
Differentiating using chain rule
![dy/dx = 4*12(1+4x)^{11} = 48(1+4x)^{11}](https://tex.z-dn.net/?f=%20dy%2Fdx%20%3D%204%2A12%281%2B4x%29%5E%7B11%7D%20%3D%2048%281%2B4x%29%5E%7B11%7D%20)
At point (0,1), we will get
![dy/dx = 48(1+4(0))^{11} = 48](https://tex.z-dn.net/?f=%20dy%2Fdx%20%3D%2048%281%2B4%280%29%29%5E%7B11%7D%20%3D%2048%20)
Now we use point slope form, which is
![y-y_{1} = m (x-x_{1})](https://tex.z-dn.net/?f=%20y-y_%7B1%7D%20%3D%20m%20%28x-x_%7B1%7D%29%20)
Substituting the values of m, and x1,y1, we will get
![y-1=48(x-0)](https://tex.z-dn.net/?f=%20y-1%3D48%28x-0%29%20)
![y = 48x+1](https://tex.z-dn.net/?f=%20y%20%3D%2048x%2B1%20)
And that's the required answer .
Use a coordinate proof to prove that mid segment mn of triangle pqr is parallel to pr and half the length of pr. which is the first best step? a. place the triangle on a coordinate grid such that vertex p is at the origin, and pr lies on x-axis. b. place the triangle on a coordinate grid such that vertex p is on y-axis and vertex r us on the x-axis
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Answer:
Sum = 4 + 5 = 9
Step-by-step explanation:
Equation
2*(x - 2)(x-2) = (x - 3)(x + 4)
Solution
2*(x^2 - 4x + 4) = x^2 + 4x - 3x - 12
2x^2 - 8x + 8 = x^2 +x - 12 Subtract the right side from the left
x^2 - 9x + 20 = 0
(x - 4)(x - 5) = 0
The possible values for x are
x - 4 = 0
x = 4
x - 5 = 0
x = 5
Check
(4 - 2)^2 = (4) = 4
(x - 3)(x + 4) = (4 - 3)(8) = 8
This checks
(5 - 2)^2 = 3^2 = 9
(5 - 3)(5 + 4) = 2 * 9 = 18