Answer:
AB ≈ 15.7 cm, BC ≈ 18.7 cm
Step-by-step explanation:
(1)
Using the Cosine rule in Δ ABD
AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )
= 153.76 + 272.25 - (409.2 cos64° )
= 426.01 - 179.38
= 246.63 ( take the square root of both sides )
AB = 
≈ 15.7 cm ( to 1 dec. place )
(2)
Calculate ∠ BCD in Δ BCD
∠ BCD = 180° - (53 + 95)° ← angle sum in triangle
∠ BCD = 180° - 148° = 32°
Using the Sine rule in Δ BCD
= 
= 
( cross- multiply )
BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )
BC = 
≈ 18.7 cm ( to 1 dec. place )
Answer:
14
Step-by-step explanation:
(5-x) +11 = 14
Answer:
44
Step-by-step explanation:
The absolute value symbols turn any negative inside of them to a positive, so your expression is ...
2 + 4·3 +5·7 +1 -6
= 2 +12 +35 +1 -6
= 44
Well, if point C is dilated by 5/3, C' should be (3*5/3, -6*5/3)
This is equivalent to Option A, (5, -10)
The straight line distance from the starting point is 41 miles.
<u>Explanation:</u>
Given:
Distance covered towards north, n = 9 miles
Distance covered towards east, e = 40 miles
Distance from the origin to the end, x = ?
If we imagine this, then the route forms a right angle triangle
where,
n is the height
e is the base
x is the hypotenuse
Using pythagoras theorm:
(x)² = (n)² + (e)²
(x)² = (9)² + (40)²
(x)² = 1681
x = 41 miles
Therefore, the straight line distance from the starting point is 41 miles.
