Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.
Explanation:
Given: A quadratic equation, kx2 - 14x + 8 = 0
Let the two zeros of the equation be α and β.
According to the given question, if one of the roots is α the other root will be 6α.
Thus, β = 6α
Hence, the two zeros are α and 6α.
We know that for a given quadratic equation ax2 + bx + c = 0
The sum of the zeros is expressed as,
α + β = - b / a
The product of the zeros is expressed as,
αβ = c / a
For the given quadratic equation kx2 - 14x + 8 = 0,
a = k, b = -14, c = 8
The sum of the zeros is:
α + 6α = 14 / k [Since the two zeros are α and 6α]
⇒ 7α = 14 / k
⇒ α = 2 / k --------------- (1)
The product of the zeros is:
⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]
⇒ 6α 2 = 8 / k
⇒ 6 (2 / k)2 = 8 / k [From (1)]
⇒ 6 × (4 / k) = 8
⇒ k = 24 / 8
⇒ k = 3
1. <span><span>20,000 </span><span>+7,000 </span><span>+500 </span><span>+40 </span><span>+9 -----WORD FORM :</span></span>twenty-seven thousand,
five hundred forty-nine
2. <span>Expanded Numbers Form:
</span>
<span><span> 700,000 </span><span>+90,000 </span><span>+2,000 </span><span>+0 </span><span>+60 </span><span>+5 </span></span>
WORD FORM : seven hundred ninety-two thousand,
sixty-five
It has 97 amounts.
43,44,45,46,47,48,49,50,
51,52,53,54,55,56,57,58,59,60
61,62,63,64,65,66,67,68,69,70 71,72,73,74,75,76,77,78,79,80
81,82,83,84,85,86,87,88,89,90
91,92,93,94,95,96,97,98,99,100
101,102,103,104,105,106,107,108,109,110
111,112,113,114,115,116,117,118,119,120
121,122,123,124,125,126,127,128,129,
130
131,132,133,134,135,136,137,138,139
Numbers between 42-140
