Answer: 40
Step-by-step explanation:
Answer:
D. 9, 12, 15
Step-by-step explanation:
You can use the Pythagorean Theorem to solve.
a^2 + b^2 = c^2
9^2 + 12^2 = c^2
81 + 144 = 225
Remember, c is squared.
The square root of 225 is 15.
D is the only answer that is correct.
Answer:
![arc\ DE=39^o](https://tex.z-dn.net/?f=arc%5C%20DE%3D39%5Eo)
Step-by-step explanation:
step 1
Find the value of w
we know that
---> by supplementary angles (form a linear pair)
substitute the given values
![(4w+8)^o+(4w+4)^o=180^o](https://tex.z-dn.net/?f=%284w%2B8%29%5Eo%2B%284w%2B4%29%5Eo%3D180%5Eo)
![8w=180-12\\8w=168\\w=21](https://tex.z-dn.net/?f=8w%3D180-12%5C%5C8w%3D168%5C%5Cw%3D21)
step 2
Find the measure of angle EPD
we know that
----> by vertical angles
substitute
![(4w+8)^o=m\angle EPD+(2w+11)^o](https://tex.z-dn.net/?f=%284w%2B8%29%5Eo%3Dm%5Cangle%20EPD%2B%282w%2B11%29%5Eo)
substitute the value of w
![(4(21)+8)^o=m\angle EPD+(2(21)+11)^o](https://tex.z-dn.net/?f=%284%2821%29%2B8%29%5Eo%3Dm%5Cangle%20EPD%2B%282%2821%29%2B11%29%5Eo)
![92^o=m\angle EPD+53^o](https://tex.z-dn.net/?f=92%5Eo%3Dm%5Cangle%20EPD%2B53%5Eo)
![m\angle EPD=92^o-53^o=39^o](https://tex.z-dn.net/?f=m%5Cangle%20EPD%3D92%5Eo-53%5Eo%3D39%5Eo)
step 3
Find the measure of arc DE
we know that
----> by central angle
therefore
![arc\ DE=39^o](https://tex.z-dn.net/?f=arc%5C%20DE%3D39%5Eo)
Answer: It would most likely be D. 90
Step-by-step explanation: When you are dealing with grades, you have to know how to average them. First step is to add all of the points that he earned, this would be 80 + 100 + 100 + 100 + 100 = 480. After you find that, you have to divide it by 5 since he takes 5 tests. 480/5 = 96. I hoped this helped you.
Answer:
- 25b = 175
Step-by-step explanation:
Since, The product of b and -25 is 175.
![\therefore \: b \times ( - 25) = 175 \\ \huge \purple{\therefore \: - 25b = 175}](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5C%3A%20b%20%5Ctimes%20%28%20-%2025%29%20%3D%20175%20%5C%5C%20%20%20%5Chuge%20%5Cpurple%7B%5Ctherefore%20%5C%3A%20-%2025b%20%3D%20175%7D)