X - 2y = -10 --> x = 2y -10

3x + 5y = 25 --> 3(2y-10) + 5y = 25 --> 11y - 30 = 25 --> 11y = 55 --> y = 5

x = 2y -10 --> x = 2(5) -10 --> x =10 -10 --> x =0

Answer (0,5)

5 0

3 years ago

Bags of sugar come in 3 sizes:

Mrrafil [7]

Answer:

Medium

Step-by-step explanation:

The computation is shown below:

The cost for the small and medium bag is shown below:

As we know that

1kg = 1000g

So 3kg = 3000g

Now for small bags

= 0.95 ÷ 250 × 3000

= £11.40

For medium bags

= £1.80 ÷ 500 × 3000

= £10.80

So here the medium bag would represent the better value

5 0

2 years ago

Please help me with 2 though 6

Ymorist [56]

It’s making me use 20 characters so here’s a lil text

4 0

3 years ago

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> $(2-4\mathbf{i})\ V$

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

5 0

2 years ago