Answer:
Option a :
Step-by-step explanation:
Given :
The drama club sold 100 tickets to a show, it had $300 in profit.
The next show, it had sold a total of 200 tickets and had a total of $700 profit.
To Find : Equation models the total profit, y, based on the number of tickets sold, x
Solution :
For 100 tickets he had $300 in profit .
⇒ (
)=(100,300)
For 200 tickets he had $700 in profit .
⇒ (
)=(200,700)
We will use point slope form i.e.
--(A)
Now, to calculate m we will use slope formula :



Now, putting values in (A)
Thus Option a is correct i.e.
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:







Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:


Therefore, 4500 end-zone tickets were sold.
Answer:

Step-by-step explanation:
A second order linear , homogeneous ordinary differential equation has form
.
Given: 
Let
be it's solution.
We get,

Since
, 
{ we know that for equation
, roots are of form
}
We get,

For two complex roots
, the general solution is of form 
i.e 
Applying conditions y(0)=1 on
, 
So, equation becomes 
On differentiating with respect to t, we get

Applying condition: y'(0)=0, we get 
Therefore,

<span>A whole number greater than 1 could be 2,3,4,5... And so on. A fraction greater than 1 is any fraction where the top number (numerator) is greater than the bottom number (denominator) for example 7/5</span>
3 carnations, you find the lowest common multiple.