Okay, I’m pretty sire this is right.
A: (-1, 3)
B: (-3, 2)
C: (-8, 3)
D: (-4, 3)
To do this problem (I am not completely confident in this) I am pretty sure you flip the signs for both the x and y values due to the rotation of the shape 180°, then add 6 to the y value.
You would have one tenths (1/10) of a chance to get a 4 on the first go. you would have four ninths (4/9) of a chance to get a number less than 5 out of the bag on the second go.
the overall probability would be two forty-fifths (2/45)
Answer:
The answer is below
Step-by-step explanation:
Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.
Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.
In quadrilateral ABCD:
∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)
Substituting:
47 + 39 + 112 + ∠D = 360
∠D + 198 = 360
∠D = 360 - 198
∠D = 162°
The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:
∠A = ∠E = 47°
∠B = ∠F = 39°
∠C = ∠G = 112°
∠D = ∠H = 162°
7 - 8 = -1
the rate of change is -1
Hope this is right,
Batgirl12
Answer:
Could you please organize your question more?
