Let the boxes be Box 1, Box 2, Box 3.
consider the 3 white balls. They can be all of them in one box:
(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)
We can have 2 in one box, and 1 in one of the remaining boxes:
(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)
and there is only one way: (1, 1, 1) to place one white ball in each box
In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.
Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.
Answer: 100
Answer:
All real numbers
Step-by-step explanation:
Linear functions have a domain and range of all real numbers because they reach from -∞ to ∞ on the x-axis and y-axis.
An example is given below. The domain and range of the function are all real numbers.
1/4(q-12) + 1/3(q+9), Then you must use the distributive property to get 1/q-3+1/3q+3. Then you simplify by combining like terms to get, 7/12q. You do not have any constants because they cross each other out.
It would be D………………………….,
Answer:
c 4/5
Step-by-step explanation:
marry chrismas
