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2 years ago

Find the value of x in the triangle shown below.

Mathematics

1 answer:

allochka39001 [22]2 years ago

8 0

Answer:

The valueof x is root under 41.

Hope this helps.

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valkas [14]

Answer: $\boxed{y=\frac{4}{5}x-2}$

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals, so as the slope of the given line is -5/4, the slope of the perpendicular line is 4/5.

Substituting into point-slope form,

$y-6=\frac{4}{5}(x-10)\\\\y-6=\frac{4}{5}x-8\\\\\boxed{y=\frac{4}{5}x-2}$

4 0

1 year ago

3 50% Draw angle ABC of size 65º. A- B X+

Snowcat [4.5K]

65* It is drawn with a round ruller...

5 0

2 years ago

Find two points on the line to be graphed 2y+16=0

yarga [219]

Y=-8 so any x with the coordinate -8 for y i guess.

4 0

3 years ago

If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).

Cloud [144]

Answer:

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + $\frac{68}{3}$

Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + C

Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1) = 3(1)⁴ - $\frac{2(1)^{3} }{3}$ - 17(1) + C

8 = 3 - $\frac{2}{3}$ - 17 + C

C =8 - 3 + 17 + $\frac{2}{3}$

C = 22 + $\frac{2}{3}$

C = $\frac{66 + 2}{3}$

C = $\frac{68}{3}$

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + $\frac{68}{3}$

7 0

3 years ago

The slope of the graphed line is 2. Which formulas 3 represent the line that is graphed? Check all that apply. y-1 = (x - 2) 3 O

yuradex [85]

Answer:

never ever learned this but maybe The answer is:

b. y - 2 = 2/3(x-1)

c. y - 4 = 2/3(x-4)

e. f(x) = 2/3 + 4/3

Step-by-step explanation:

bce

3 0

2 years ago