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Mrrafil [7]
2 years ago
9

Max decides to use 700 rubber bands to make 8 balls. Is it reasonable to say he would use about 90 rubber bands to make each bal

l? Explain.
Mathematics
1 answer:
topjm [15]2 years ago
7 0

Answer:

he would have used about 87 bands for each ball so if you round to the nearest ten yes it is reasonable to say he used 90 bands per ball

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Does anyone know how to do this
Doss [256]

Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

Step-by-step explanation:

Considering the quadrilateral with vertices

d(0,0)

i(5,5)

n(8,4)

g(7,1)

Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

From the figure a, it is clear that the quadrilateral has

Two pairs of sides

Each pair having two equal-length sides which are adjacent

The angles being equal where the two pairs meet

Diagonals as shown in dashed lines cross at right angles,  and one of the diagonals does bisect the other - cuts equally in half

Please check the attached figure a.

4 0
3 years ago
An office is divided into 8 cubicles. How many of the cubicles are carpeted if only 1/4 of the cubicles are carpeted?
djyliett [7]
U have to do it like this 1/4 and 8/100
6 0
3 years ago
Express 3950000000 in scientific notation.
Nesterboy [21]
3.95*10^9 move the decimal to the left untill it is in between the last ans 2nd to last number
7 0
3 years ago
The area of the postcard is 24 square inches. What is the width b of the message (in inches)?
MAXImum [283]
Area of rectangular post card = length x width
For the given post card: 
length = 4 in
width = (3+b) in
area = 24 in^2

So, substituting in the equation of the area:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
4 0
3 years ago
What is the other square root of 119 + 120i?
MakcuM [25]

Answer:

\sqrt{119+120 i}=\pm (12.24+i 4.90)

Step-by-step explanation:

Given

z = 119 + 120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85  

p^2=149.85

thus p=\pm 12.24

q=\pm 4.90

thus,

\sqrt{119+120 i}=\pm (12.24+i 4.90)

8 0
2 years ago
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