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postnew [5]
3 years ago
7

What adds for -26 and multiplys for 10

Mathematics
1 answer:
inn [45]3 years ago
6 0
2 * 5 would give you 10 
and

-30 + 4 would give you -26 :)

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Check all statements that are equivalent to If the sky is not clear, then you don't see the stars ? a. Clear sky is necessary an
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Answer: The answer is G

Step-by-step explanation:

If you don't see the stars, then the sky is not clear. This statement is equivalent to saying "If the sky is not clear, then you don't see the stars", because if you rearrange both statements you will find out that they are equivalent to each other.

Mark out all the words in each statement, you will discover that at the end you will have no word left on both side, its just as good as saying 1 - 1 = 0.

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3 years ago
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When adding integers with the same sign you should
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To add integers having the same sign, keep the same sign and add the absolute value of each number.

Step-by-step explanation:

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Harry cycles 8 kilometres in 30 minutes.<br> Calculate his average speed, in km/h.
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5 to the power of 2 + (5.2 - 3.1)
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Step-by-step explanation:

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3 years ago
URGENT!!!!!<br> Work out the image attached<br> Include Workings
Ann [662]

9514 1404 393

Answer:

  • 17.8 km
  • 80.4 m

Step-by-step explanation:

The first attachment shows the sort of geometry involved. The line of sight from the top of the lighthouse makes a tangent with the earth's surface at the horizon (neglecting optical effects due to the atmosphere).

The hypotenuse of the relevant triangle is (r+h), and the angle is adjacent to the radius, r. Then the cosine relation applies:

  Cos = Adjacent/Hypotenuse

  cos(α) = r/(r+h)

We note that the radius is in km, and the length h is given in meters, so we need to do a conversion to put the numbers in this formula. We don't care so much about the angle itself, but we need its value to find the length of the arc along the earth's surface. That is ...

  s = r·α

so, the distance of interest is found from ...

  cos(α) = 6367/(6367 +0.025)

  r·α = 6367·arccos(6367/6367.025) ≈ 17.84 . . . km

The horizon is about 17.8 km from the observer.

__

The second problem requires we find the height value that makes the distance 32 km.

  32 = r·α = 6367·arccos(6367/(6367 +h))

Dividing by the earth's radius and taking the cosine, we have ...

  cos(32/6367) = 6367/(6367 +h)

  h = 6367 -6367/cos(32/6367) ≈ 6367.0804 -6367 = 0.0804 . . . km

The cliffs must be about 80.4 meters high for it to be possible to see that distance.

6 0
3 years ago
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